Behaviour of Dirichlet L-Function of Principal Character at 1

Theorem

For principal Dirichlet character χ0 modulo q, we have that

lims1+(s1)L(s,χ0)=φ(q)q.

and hence

lims1+L(s,χ0)=.

That is (Ls,χ0) has a simple pole at 1 with residue φ(q)q.

Proof

This follows from this formula and the behaviour of the Riemann zeta function. In particular we have

lims1+(s1)L(s,χ0)=lims1+ζ(s)pq(11ps)=lims1+(s1)ζ(s)pq(11ps)=lims1+((s1)ζ(s))lims1+(pq(11ps))=pq(11p)=1q(qpq(11p))=φ(q)q

noting the Euler totient function formula.

Then clearly because s10 as s1+ it would induce a contradiction for L(s,χ0) to be bounded as s1+.